Originally posted by David W
[b]:D:D Quickmick
RE: Forces in drop jumps.
Under eccentric conditions forces upto 2 times max. isometric force are possible. More than that is biomechanically impossible!
F=ma
Since, a~9.8m/s^2 an individual would have to fall for 1s in order to induce a force ~10x mass!!
Using the laws of constant acceleration:
d=0.5 a.t^2
Therefore, d=0.5x9.8x1
d=4.9m!!!
Who could perform a drop jump from 4.9m?? :D:D [/b]
i hate to be picky about this, but wasn’t the number quoted for a depth (involving jumping once one hits the ground) jump rather than a drop jump (just landing)? If one just drops and lands, your math is correct. However, if one jumps with a sigificantly short ground contact time, this number will be higher:
using momentum P = impulse I
P = I = integral force d time // assuming constant force
P = I = F * t
Say you depth jumped from a .25 meter box,
.25 = ~10/2time^2
root(.05) = time
v = atime
vel = ~2.24 m/s
momentum (pointed towards ground) = 2.24*mass
Lets say that we want the box height as our target height
assuming cons of Energy (good enough): .5mv^2 = mg*.25
v_at takeoff = root(.5)
Change in mometum needed is Massroot(.5) - (-2.24mass)
or ~2.947*mass
using the impulse equation:
integral of Force with respect to time = 2.947mass
assuming force is a constant: F = 2.947mass/contact time
I don’t know what the contact times are off-hand but if they are in the ball park of a half a second then the multiplier is about 4*mass. If the time is less than a half a second the force is even more. (note: if the force curve is linear, then the peak force is higher, i assume this trend holds true for higher orders)
Sorry about the convoluded physics, the engineer took over . If my numbers are off or i made a bad assumption, let me know, i am not used to typing a problem as i solve it.
In more relation to the actual topic, i believe that weights are useful for sprinting if that part of the Force Velocity Curve is not well trained. Both Sprinting and plyo’s (as mathmatically illustrated) only train one part of the curve. Weights train a different part.